Answers to questions you were afraid to ask

[crinolynne]

Originally Posted by Brian249x

Is sitting on your gun and accidentally blowing your dick off funny or tragic?

https://www.huffingtonpost.com/entry...b05c37bb7f3de8

Perhaps this is funny when it happens to someone else. Does anybody know if his girlfriend stuck with him?

It's an example of Darwin in action...

[MaxJoker]

Originally Posted by crinolynne

It's an example of Darwin in action...

For the contribution

[mmephistoo]

Hi there,
I was afraid to ask this type of mathematic question. I don't know where to post but I hope someone could help me writing this equation:


A book writer published a novel. The first 450 copy cost 60$ a copy. Any other copy after that cost 5$ each. How many copies he has to publish and sell to break even, given that he sells a copy with 28.5$
Any mathematicians here?!

Thanks in advance

[cicciobuki]

Originally Posted by mmephistoo

Hi there,
I was afraid to ask this type of mathematic question. I don't know where to post but I hope someone could help me writing this equation:


A book writer published a novel. The first 450 copy cost 60$ a copy. Any other copy after that cost 5$ each. How many copies he has to publish and sell to break even, given that he sells a copy with 28.5$
Any mathematicians here?!

Thanks in advance

About 1053 copies i think (assuming all copies would be sold)

450 x 60 = 27.000
600 x 5 = 3.000
total cost: 30.000 $

Selling 1050 copies at 28,5 = 29.925 $
Netto profit per extra printed & sold copy would be 23,5$ so add 3 more copies and you're almost even. Theoretically. i think.

[mmephistoo]

Originally Posted by cicciobuki

About 1053 copies i think (assuming all copies would be sold)

450 x 60 = 27.000
600 x 5 = 3.000
total cost: 30.000 $

Selling 1050 copies at 28,5 = 29.925 $
Netto profit per extra printed & sold copy would be 23,5$ so add 3 more copies and you're almost even. Theoretically. i think.

Thank you.
The answer is roughly 1053.19 but what I was looking for is the equation.

[cicciobuki]

Originally Posted by mmephistoo

Thank you.
The answer is roughly 1053.19 but what I was looking for is the equation.

Ahh, that would require real math, and i'm not so good at that

[Roubignol]

Originally Posted by mmephistoo

Hi there,
I was afraid to ask this type of mathematic question. I don't know where to post but I hope someone could help me writing this equation:


A book writer published a novel. The first 450 copy cost 60$ a copy. Any other copy after that cost 5$ each. How many copies he has to publish and sell to break even, given that he sells a copy with 28.5$
Any mathematicians here?!

Thanks in advance

450*60+5*Y = (450+Y)*28.5
Y= 450*(60-28.5)/(28.5-5) = 603.191

Total books to break even = 450+Y = 1053.19

So 1054 books.

[mmephistoo]

Originally Posted by Roubignol

450*60+5*Y = (450+Y)*28.5
Y= 450*(60-28.5)/(28.5-5) = 603.191

Total books to break even = 450+Y = 1053.19

So 1054 books.

First 2 lines are excellent, but why did we add up 450 to Y? I know that is the rough number, but why?

[Roubignol]

Originally Posted by mmephistoo

First 2 lines are excellent, but why did we add up 450 to Y? I know that is the rough number, but why?

My mother tongue is French... I didn't take care that you wrote "450 copy cost" instead of "450 copies cost".


Edit: But... even after that... isn't there a grammar mistake? Any other copy after that costs

So... what is the trap?

[mmephistoo]

Originally Posted by Roubignol

450*60+5*Y = (450+Y)*28.5
Y= 450*(60-28.5)/(28.5-5) = 603.191

Total books to break even = 450+Y = 1053.19

So 1054 books.

I think I figure it out, talking to my friend based on your equation:
X is the total number of copies needed = Y (copies after the first 450 ones) + 450
Y in your equation resembles exactly that.
Y= 603.19
X= 450+603.19(Y)=1053.19
So this is it. Thank you.